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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Mar 28, 2016 at 23:57 history edited user45947 CC BY-SA 3.0
Fixed typo.
Mar 28, 2016 at 23:55 comment added user45947 The correct expression should of course be $E[\pi_{rm}] = \sum_{n\leq x} W(\sqrt{n})$. I'll edit the original post accordingly. I assume only that $P(a \equiv b \pmod{p}) = 1/p$ for all $0\leq b < p$ and $p\leq \sqrt{x}$, or equivalently, that $P(a \equiv b \pmod{P(\sqrt{x}))} = 1/P(\sqrt{x})$ for all $0\leq b < P(\sqrt{x})$.
Mar 21, 2016 at 2:23 comment added reuns when you write $E[\pi_{rm}(x)] = \sum_{n \le x} W(\sqrt{x})$ you are assuming that $E[a] = 0$ and $P(a \equiv b \pmod p) = 1/p$ for every $b$ and prime $p \le x$ ?
Mar 9, 2016 at 19:08 history edited user45947 CC BY-SA 3.0
added 80 characters in body
Mar 9, 2016 at 11:48 history asked user45947 CC BY-SA 3.0