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Mar 15, 2016 at 6:09 vote accept SashaP
Mar 12, 2016 at 14:18 answer added Piotr Achinger timeline score: 4
Mar 12, 2016 at 14:10 comment added Piotr Achinger What do you mean by `$A$ lifts to $W(k)$'? Do you want the lift to be a scheme or a formal scheme?
Mar 9, 2016 at 4:24 comment added nfdc23 I assume $k$ is perfect. Let $A'$ be the chosen lift of $A$, giving $B'$ and $T'$ lifting $B$ and $T$ respectively. Using the canonical link between such extensions and line bundles on $B'$ arising from the dual abelian scheme when $T = {\rm{GL}}_1$ (so we can regard $B'$ as primary and $A'$ as secondary), in general $A'$ corresponds to a $W(k)$-point $\xi$ of ${B'}^{\vee} \otimes {\rm{X}}^{\ast}(T)$ (using the dual abelian scheme). So the necessary and sufficient condition is that Frobenius of $B$ lifts to $B'$ and its dual map along with Frobenius for $T$ carries $\xi^{(p)}$ to $\xi$.
Mar 8, 2016 at 21:03 history asked SashaP CC BY-SA 3.0