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Mar 9, 2016 at 16:06 comment added Peter Following the suggestions of Sebastian Goette I have posted the question on math.stackexchange ( math.stackexchange.com/questions/1690221/…)
Mar 9, 2016 at 15:45 comment added Peter For the particular case of rotations, function values can be approximated as $\hat{\Phi}(x) = \Phi(x) - \nabla\Phi(x)^T\cdot[x]_{\times}\cdot\omega$ with $[.]_{\times}$ the skew symmetric cross product matrix, and $\omega$ the vector of exponential rotation coordinates. The term $[x]_{\times}\cdot\omega$ determines a tangent vector field for the curves under the group action. Therefore function values along the slightly perturbed slice are approximated in the form $\hat{\Phi} = \Phi + \sum_{i=1}^3 \omega_i\mathcal{L}_i$. I would like to know if this process can be replicated for $SE(3)$?
Mar 9, 2016 at 15:45 comment added Peter I consider the slice to be a two-dimensional linear submanifold $\mathcal{S}$ of $\mathcal{M}=\mathbb{R}^3$. The action of the transformation group ($SE(3)$) maps points $x$ of $\mathcal{S}$ along curves, corresponding to flows of vector fields (diffeomorphisms), "induced" by the generators of the group. My question is if approximations to the function values $\Phi$ at the transformed points (jet) can be consistently provided with respect to arbitrary infinitesimal actions of the group, using a linear combination of basis vectors with coefficients of the Lie-algebra.
Mar 8, 2016 at 19:13 review Close votes
Mar 9, 2016 at 8:33
Mar 8, 2016 at 18:55 comment added Sebastian Goette Welcome to mathoverflow. What do we know about $\Omega^\Phi$? Do you mean by "slice" the set $\Omega_s=s^{-1}\cap\mathbb R^2\times\{0\}$? And by "manifold of slices" the subset of $SE(3)$ such that $\Omega_s\ne\emptyset$? Please clarify this, and think about posting this question on math.stackexchange, as this does not really look like a research level question.
Mar 8, 2016 at 18:30 review First posts
Mar 8, 2016 at 18:55
Mar 8, 2016 at 18:27 history asked Peter CC BY-SA 3.0