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Apr 10, 2020 at 18:56 comment added Thomas Dybdahl Ahle Very cool, so basically we use the Markov like inequality $E[f(X)] \ge \Pr[0 \le x\le r] \min_{0\le x \le r} f(x)$ for a cleverly chosen $f$.
Mar 8, 2016 at 16:29 comment added passerby51 Here is another observation which is intriguing: The lower bound is decreasing in $t$ while the probably (LHS) is increasing, so it seems the bound is good for small values of $t$. With $a = (1+\sqrt{2})/2$, the lower bound seems to be maximized at $t = 3a/2$. So for all $t > 3a/2$, we should just use the bound for $t = 3a/2$.
Mar 8, 2016 at 15:48 comment added passerby51 Thanks. This is interesting. I am intrigued by the word "standard". In what context is this standard? (I thought anything involving a cubic polynomial is fairly nonstandard!)
Mar 7, 2016 at 22:42 history answered Robert Israel CC BY-SA 3.0