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Feb 13, 2019 at 3:34 comment added Mozibur Ullah +1: nice answer, I feel I almost understand Cosheaves now ...!
Mar 7, 2016 at 18:40 comment added Simon Henry Indeed (when n>0): if the space is hausdorff the only points where the stalk is non-zero are the isolated points. For the reference, I will try to find something. But roughly if you have a co-complete monoidal closed category $C$ (so sets, abelian group, vector spaces etc...) you can show that there is an equivalence of category between cosheaves with values in $C$ and co-limit preserving $C$-enriched functor from $Sh(X,C)$ to $C$. So if you think as $C$- valued sheaves as "functions with values in $C$", cosheaves are the things that allows to integrate those functions.
Mar 7, 2016 at 18:26 comment added Jo Wehler As I understand: In case of X an open subset of R^n the stalks are zero. - Can you name a reference concerning the heuristics "co-sheaves as measures", thanks.
Mar 7, 2016 at 18:23 vote accept Jo Wehler
Mar 7, 2016 at 18:16 history edited Simon Henry CC BY-SA 3.0
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Mar 7, 2016 at 18:05 history answered Simon Henry CC BY-SA 3.0