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Aug 30, 2016 at 1:12 answer added David Wood timeline score: 5
May 5, 2016 at 8:26 vote accept Dominic van der Zypen
May 4, 2016 at 15:50 answer added Tony Huynh timeline score: 6
Mar 16, 2016 at 18:23 answer added Ilya Bogdanov timeline score: 7
Mar 8, 2016 at 19:47 comment added Dominic van der Zypen Thats right, proving this would provide a negative answer to my question.
Mar 8, 2016 at 16:15 comment added logicute Don't you rather conjecture that every graph is at most $3$-majority-colorable? Which amounts to saying that every graph can be partitioned in $C_1, C_2, C_3$ such that every vertex in $C_i$ doesn't have more edges coming from $C_i$ than from $V\setminus C_i$.
Mar 7, 2016 at 15:42 history edited Dominic van der Zypen CC BY-SA 3.0
Question was not clear
Mar 7, 2016 at 15:39 comment added Dominic van der Zypen Right - I'll edit my post accordingly.
Mar 7, 2016 at 15:37 comment added Benoît Kloeckner Nice concept, but you should make clear what your question is.
Mar 7, 2016 at 15:27 history asked Dominic van der Zypen CC BY-SA 3.0