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Mar 6, 2016 at 3:40 vote accept Ron
Mar 5, 2016 at 19:50 comment added user26857 Cross-posted: math.stackexchange.com/questions/1683803/…
Mar 5, 2016 at 12:56 answer added Jeremy Rickard timeline score: 6
Mar 5, 2016 at 11:55 comment added Piotr Achinger @Vinteuil you are right, I misunderstood the question. Perhaps it is still true that an $A$-flat $B$-module is a colimit of $A$-free $B$-modules, but it is unclear whether $\bigwedge^m_B$ of an $A$-free $B$-module is $A$-free...
Mar 5, 2016 at 10:54 comment added Piotr Achinger I think yes: (1) by Lazard's theorem, flat modules are colimits of free modules, (2) your functors commute with colimits and (3) they map free modules to free modules.
Mar 5, 2016 at 9:54 history asked Ron CC BY-SA 3.0