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Mar 21, 2016 at 22:44 answer added Thomas Benjamin timeline score: 0
Mar 16, 2016 at 23:03 comment added Thomas Benjamin To all...it might help to read Dr. Fontanella's slide presentation, "On the definitional character of axioms", to understand the import of her question (and to understand why she asked it--this presentation is available on her homepage under "Talks"). It touches on topics presented in her question.
Mar 16, 2016 at 9:54 history edited Mikhail Katz CC BY-SA 3.0
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Mar 16, 2016 at 9:06 answer added Thomas Klimpel timeline score: 0
Mar 4, 2016 at 16:32 answer added Andreas Blass timeline score: 8
Mar 4, 2016 at 16:19 history reopened Joel David Hamkins
Joonas Ilmavirta
Wolfgang
Asaf Karagila
Andreas Blass
Mar 4, 2016 at 16:12 comment added Nik Weaver Are you essentially asking whether most mathematicians consider proper classes to be "objects" which are just as "real" as sets? I suspect that most people may not have a really well thought out opinion on the question. (Or even the question, in what sense are sets "real objects".)
Mar 4, 2016 at 15:40 history edited Laura Fontanella CC BY-SA 3.0
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Mar 4, 2016 at 14:31 history edited Laura Fontanella CC BY-SA 3.0
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Mar 4, 2016 at 13:38 review Reopen votes
Mar 4, 2016 at 16:22
Mar 4, 2016 at 13:19 history edited Laura Fontanella CC BY-SA 3.0
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Mar 4, 2016 at 10:19 comment added Laura Fontanella I understand your perplexities, so I should better explain my motivations. As a set theorist, I know the meaning of this statement and how one proves it from ZF, but I'm interested in how my colleagues interpret it, like a poll. For instance, Joel used the expressions "there is no set of all sets" and "there is no universal set", another way to read it is "the class of all sets is not a set". I believe that each of those expressions hides different philosophical standpoints, so I'm interested in what is your favorite interpretation. If that's an inappropriate use of MO, I apologise.
Mar 3, 2016 at 15:56 comment added Joel David Hamkins In plain language, the assertion expresses: there is no set of all sets. That is, there is no set $x$ for which every set $y$ is a member of $x$. This is easy to prove in ZF, for if there were such a universal set $x$, then by the separation axiom the collection $z=\{ y\in x\mid y\notin y\}$ would also exist as a set, and in this case, since $z\in x$, we would have $z\in z$ just in case $z\notin z$, which is a contradiction. So there can be no universal set. This argument is fundamentally related to the Russell paradox.
Mar 3, 2016 at 14:00 history made wiki Post Made Community Wiki by Todd Trimble
Mar 3, 2016 at 14:00 comment added Todd Trimble Welcome to MO, Dr. Fontanella (on assumption this is your page: logique.jussieu.fr/~fontanella). Please excuse what may seem a summary dismissal of your question. A number of users flagged the question as one unlikely to be asked by a professional mathematician, so there's a good chance it was received differently from how you intended it. The question can be reopened, but I suggest (in keeping with site norms) that some further explanation/context/motivation be provided, to make clearer what you are intending. I'm also making this Community Wiki because many answers are possible.
Mar 3, 2016 at 13:29 history closed Emil Jeřábek
Andrés E. Caicedo
Todd Trimble
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Mar 3, 2016 at 12:04 review Close votes
Mar 3, 2016 at 13:30
Mar 3, 2016 at 11:39 review First posts
Mar 3, 2016 at 11:52
Mar 3, 2016 at 11:30 history asked Laura Fontanella CC BY-SA 3.0