Timeline for How do Schubert classes form a basis for $H^{*}(Gr(k, n))$?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 29, 2016 at 0:55 | comment | added | Ben Webster♦ | @Libertron All I used was the Eilenrod-Steenrod axioms (en.wikipedia.org/wiki/Eilenberg%E2%80%93Steenrod_axioms), so any cohomology theory satisfying those (such as singular cohomology) would work. | |
| Feb 28, 2016 at 23:34 | comment | added | Sam Hopkins | He probably means singular (co)homology: en.wikipedia.org/wiki/Singular_homology | |
| Feb 28, 2016 at 23:25 | comment | added | Libertron | By usual do you mean simplicial? | |
| Feb 28, 2016 at 23:23 | vote | accept | Libertron | ||
| Feb 28, 2016 at 23:12 | history | answered | Ben Webster♦ | CC BY-SA 3.0 |