Timeline for A question on determinant of a matrix polynomial
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 12, 2016 at 13:45 | history | edited | R.T MAN | CC BY-SA 3.0 |
added 8 characters in body
|
| Feb 28, 2016 at 18:01 | vote | accept | R.T MAN | ||
| Feb 26, 2016 at 18:13 | answer | added | Mark Fischler | timeline score: 3 | |
| Feb 26, 2016 at 18:05 | comment | added | R.T MAN | @MarkFischler - Ok, Now let, if $Q(x)$ is even function, why does $p(x,y)=0 $? | |
| Feb 26, 2016 at 17:50 | answer | added | Marcel | timeline score: 3 | |
| Feb 26, 2016 at 17:31 | comment | added | Mark Fischler | @thedude Let me try to clarify what the question is "obviously" about (@RTMAN correct me if this is wrong): That determinant is obviously a real function of $x$ and $y$ ($D(x,y)$. But functions of the form of a polynomial in the two variables, plus another polynomial times $\sqrt{x^2+y^2}$, are a rather thin subset of all possible functions. Prove that $D(x,y)$ is of that form. | |
| Feb 26, 2016 at 16:38 | history | edited | R.T MAN | CC BY-SA 3.0 |
added 63 characters in body
|
| Feb 26, 2016 at 16:12 | comment | added | R.T MAN | @IgorKhavkine - I had a mistake before.Fixed it. | |
| Feb 26, 2016 at 15:39 | history | edited | R.T MAN | CC BY-SA 3.0 |
deleted 14 characters in body
|
| Feb 26, 2016 at 15:19 | comment | added | Igor Khavkine | The notation is very confusing. Is $p(x,y)$ fixed in advance or is it to be determined to satisfy the equation in your question? What is the relation between $q(x,y)$ and $\mathrm{q}(\lambda)$? Do you distinguish between $q$ and $\mathrm{q}$, or between $w$ and $\mathrm{w}$, etc.? Better not use \rm in math formulas unless you really know what you are doing. | |
| Feb 26, 2016 at 14:44 | comment | added | thedude | If $t$ is real, and $P^*P$ is also real, isn't it obvious that the determinant is real? | |
| Feb 26, 2016 at 14:16 | history | edited | R.T MAN | CC BY-SA 3.0 |
deleted 43 characters in body
|
| Feb 26, 2016 at 14:06 | comment | added | thedude | 1) If $t$ is an eigenvalue, shoudn't that determinant be zero? 2) Since you don't say anything about $q(x,y)$ and $p(x,y)$, you are just asking why the determinant is real? | |
| Feb 26, 2016 at 14:01 | history | asked | R.T MAN | CC BY-SA 3.0 |