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Feb 26, 2016 at 18:05 vote accept peter
Feb 26, 2016 at 14:59 answer added Robert Bryant timeline score: 7
Feb 26, 2016 at 13:51 comment added David E Speyer It seems to me that $Q_f^{\mathbb{C}} \cong Q_f \otimes \mathbb{C}$, so $\mu_{\mathbb{R}} = \mu_{\mathbb{C}}$. Am I missing something?
Feb 26, 2016 at 11:42 history edited peter CC BY-SA 3.0
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Feb 25, 2016 at 21:49 history edited peter CC BY-SA 3.0
deleted 2 characters in body; edited tags
Feb 25, 2016 at 21:38 history asked peter CC BY-SA 3.0