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Feb 29, 2016 at 9:01 comment added Kaveh Sorry, I misspelled . g is a metric and $ T_g$ must be replaced by $T_g Riem (M)$. It is infinite dimensional Frechet manifold. The only thing that I found about injectivity radius is that it is discontinuous.
Feb 25, 2016 at 14:02 comment added Thomas Richard By $T_gM$ you mean $T_gRiem(M)$ ? So you're asking about the injectivity radius of an infinite dimensional Riemannian manifold ? I suspect the situation can be pretty bad.
Feb 25, 2016 at 12:13 comment added Alex M. What is $g$? Since you write $T_g M$, it seems to be a point of $M$; why does it have an inverse, is $M$ a Lie group? What does that trace mean? Where does one use $Rim (M)$? What is $vol(g)$?
Feb 25, 2016 at 11:41 history edited Kaveh CC BY-SA 3.0
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Feb 25, 2016 at 11:36 history edited Kaveh CC BY-SA 3.0
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Feb 25, 2016 at 11:21 history asked Kaveh CC BY-SA 3.0