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Feb 21, 2016 at 19:05 vote accept Andreas Rüdinger
Feb 21, 2016 at 17:37 comment added Will Sawin @AndreasRüdinger Yes, this is clear, as the roots and critical points depend continuously on the value of a complex polynomial.
Feb 21, 2016 at 17:28 comment added Andreas Rüdinger Thank you, you are right. However, I wanted $f$ also to be generic in the sense that $f'$ has pairwise distinct zeros (which I didn't say in the question; I will edit it accordingly). Perhaps a slight modification of your answer will still give a counterexample.
Feb 21, 2016 at 17:14 history answered Lev Borisov CC BY-SA 3.0