Timeline for Combination of Generating Functions
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Nov 21, 2019 at 18:46 | comment | added | Eleven-Eleven | I think I fixed it. I haven't looked at this problem in a while, so I had to figure out what it was. The coefficients $a,b$ in the argument of $H$ are dependent on both $i$ and $j$. The main difference in the two expressions is that the top is the sum of the individual $H$ over $j$ where the bottom is not, only over some (any) fixed $k$ | |
| Nov 21, 2019 at 18:40 | history | edited | Eleven-Eleven | CC BY-SA 4.0 |
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| Nov 21, 2019 at 18:35 | history | edited | Eleven-Eleven | CC BY-SA 4.0 |
added 63 characters in body
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| Nov 21, 2019 at 18:24 | history | edited | Eleven-Eleven | CC BY-SA 4.0 |
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| Nov 21, 2019 at 18:23 | comment | added | Eleven-Eleven | $f(n)$ would be a factor in $n$ dependent on the sum. Note the Euler / Bernoulli Polynomial equation in my post, the $f(n)=2^n/n$. I'm about to fix the sums as well too. | |
| S Mar 2, 2016 at 13:02 | history | bounty ended | CommunityBot | ||
| S Mar 2, 2016 at 13:02 | history | notice removed | CommunityBot | ||
| S Feb 23, 2016 at 11:53 | history | bounty started | Eleven-Eleven | ||
| S Feb 23, 2016 at 11:53 | history | notice added | Eleven-Eleven | Canonical answer required | |
| Feb 22, 2016 at 16:03 | history | edited | Eleven-Eleven | CC BY-SA 3.0 |
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| Feb 21, 2016 at 4:02 | history | edited | Eleven-Eleven | CC BY-SA 3.0 |
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| Feb 21, 2016 at 3:57 | history | asked | Eleven-Eleven | CC BY-SA 3.0 |