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Feb 20, 2016 at 12:52 comment added Joseph O'Rourke @ManfredWeis: Thanks for those clarifications.
Feb 20, 2016 at 12:38 comment added Manfred Weis the non-optimal tours in your examples correspond to exchanging $3$ edges of the optimal tour.
Feb 20, 2016 at 12:35 comment added Manfred Weis The optimal tour through $n$ points is always $n$-optimal; the thing about $k$-optimality is that the tour can't be improved, no matter which subset of $k$ edges is exchanged; that means, that for checking the next set $k$ edges, the previous change has to be reverted. A different aspect is however, that i suspect that in case of a unique $k$-optimal tour it is possible to find the overall optimal tour in $O(n^{k+1})$ time by repeatedly replacing non-optimal subsets of $k$ edges.
Feb 20, 2016 at 12:11 history edited Joseph O'Rourke CC BY-SA 3.0
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Feb 20, 2016 at 11:55 history answered Joseph O'Rourke CC BY-SA 3.0