Timeline for Using wavelets to capture the $L^2$ norm of $f''$
Current License: CC BY-SA 3.0
10 events
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| Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
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| Mar 24, 2016 at 22:57 | comment | added | reuns | @SilviaGhinassi : the wavelet transform is not so simple to compute, that's why I told you to look at the discrete (Haar) wavelet transform (the normal Haar wavelet transform for a function being constant on any $[2^{-k}n,2^{-k}(n+1)[$ interval) which has the same complexity as the discrete Fourier transform, and indeed the algorithms are very very close, and for both there exists the fast transforms (FFT and fast wavelet transform) which are even closer | |
| Mar 24, 2016 at 21:20 | history | edited | Silvia Ghinassi | CC BY-SA 3.0 |
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| Mar 24, 2016 at 21:13 | history | edited | Silvia Ghinassi | CC BY-SA 3.0 |
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| Mar 24, 2016 at 21:06 | history | edited | Silvia Ghinassi | CC BY-SA 3.0 |
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| Feb 20, 2016 at 9:10 | answer | added | Jean Duchon | timeline score: 1 | |
| Feb 18, 2016 at 14:20 | comment | added | Silvia Ghinassi | Let me say it better: I am attached to the simplicity of computation, because I am attached to the nice geometric interpretation I can give it. @JeanDuchon | |
| Feb 18, 2016 at 14:03 | comment | added | Silvia Ghinassi | Yeah, I am in $\mathbb R$, and besides that, any coefficient that depends on something smoother (like Fourier ones), seems to me that the become much harder to compute (using the Haar system all you have to do is subtraction and division of some values of my function). But, maybe I am wrong, and my problem is exactly insisting in Haar wavelets. | |
| Feb 18, 2016 at 12:17 | comment | added | Jean Duchon | You seem to insist at expressing (or framing) some norm of $f''$ as a sum of wavelet coefficients, and this is certainly possible with any smooth enough wavelet (not just the Haar system, then). But why not just use the Fourier base on an interval ? Or do you mean $L^2(\mathbb R)$ ? | |
| Feb 17, 2016 at 23:25 | history | asked | Silvia Ghinassi | CC BY-SA 3.0 |