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Apr 13, 2017 at 12:58 history edited CommunityBot
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May 10, 2010 at 20:13 comment added user2734 @Qiaochu Yuan: Please note that I have corrected the part concerning your dynamical systems example.
May 5, 2010 at 15:14 vote accept Qiaochu Yuan
May 5, 2010 at 12:51 answer added user2734 timeline score: 7
May 1, 2010 at 18:59 history edited Qiaochu Yuan CC BY-SA 2.5
added 161 characters in body
May 1, 2010 at 18:19 history edited Qiaochu Yuan CC BY-SA 2.5
added 371 characters in body
May 1, 2010 at 18:17 comment added Qiaochu Yuan @Tilman: I didn't know that - thanks! I'll give a different example.
May 1, 2010 at 13:03 comment added Tilman My comment was referring to OP's motivating example.
May 1, 2010 at 10:48 comment added Martin Brandenburg @unknown (google): no you're right.
May 1, 2010 at 10:10 comment added user2734 @Tilman: My comments referred only to the first part of the question. Is there something wrong with what I said?
May 1, 2010 at 8:17 comment added Tilman The problem with your example is that the homotopy category doesn't even have limits. And even if you try to lift this into a model-category setting and use the homotopy limit, $\pi_1$ doesn't send those to limits (take a pullback of a fibration as an example, where you get a Mayer-Vietoris-like sequence involving all $\pi_i$).
Apr 30, 2010 at 23:07 comment added user2734 (...cont'd) But $F\tau$ is such a lift, and hence we're done. Now, if I am not mistaken, for any $\tau$-algebra the forgetful functor to $\mathbf{Set}$ creates limits. (I once proved it for solving some exercise, but I'm not sure if my proof is correct, since it has been quite a while since I did it).
Apr 30, 2010 at 23:07 comment added user2734 If the forgetful functor creates limits, then I think you get what you want. In detail: Let $J$ be an index category, and let $J\stackrel{T}{\to}C\stackrel{F}{\to}D\stackrel{U}{\to}\mathbf{Set}$ be functors. Suppose that $UF$ preserves limits and $U$ creates limits. Suppose that $\tau\colon \ell\to T$ is a limiting cone in $C$. Since $UF$ preserves limits, $UF\tau\colon UF\ell\to UFT$ is a limiting cone. As $U$ creates limits, there is a unique lifting of $UF\tau$ to a cone in $D$, and this cone is a limiting cone. (to be continued...)
Apr 30, 2010 at 22:41 history edited Harry Gindi CC BY-SA 2.5
edited body
Apr 30, 2010 at 22:32 history asked Qiaochu Yuan CC BY-SA 2.5