Skip to main content
9 events
when toggle format what by license comment
Feb 21, 2016 at 7:35 vote accept Jianrong Li
Feb 16, 2016 at 18:00 comment added YCor You haven't moved the question, you have cross-posted it.
Feb 16, 2016 at 17:58 history closed Vladimir Dotsenko
Stefan Kohl
Wolfgang
Stefan Waldmann
YCor
Not suitable for this site
Feb 16, 2016 at 13:34 answer added Dietrich Burde timeline score: 2
Feb 16, 2016 at 13:20 comment added Jianrong Li @Vladimir Dotsenko, thank you very much. I moved the question to MSE.
Feb 16, 2016 at 12:34 review Close votes
Feb 16, 2016 at 17:59
Feb 16, 2016 at 12:20 comment added YCor The conclusion fails in general. Take $\mathfrak{g}$ 1-dimensional abelian, $V$ the 2-dimensional module defined by $x(y,z)=(xz,0)$. Define $f(x)=(0,x)$, so $xf(y)=(xy,0)$ is symmetric in $x,y$ and thus $f([x,y]-xf(y)+yf(x)=0$ for all $x,y$. It does not have the form $f(x)=xv=x(v_1,v_2)=(xv_2,0)$.
Feb 16, 2016 at 12:17 comment added Vladimir Dotsenko Cohomology of $gl_n$ with coefficients in finite-dimensional modules is well known. You are asking a question about $H^1$. If figuring this out and locating the answer in the literature leads to substantial difficulties, you should be asking it on MSE, not MO.
Feb 16, 2016 at 11:58 history asked Jianrong Li CC BY-SA 3.0