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Feb 16, 2016 at 22:30 comment added Theo Johnson-Freyd Ah, sorry for the notation! By "is the identity on finite sets" I mean something less strict than it sounds --- perhaps I should have said "is the identity on finite cardinalities".
Feb 16, 2016 at 2:25 comment added Joel David Hamkins If what you want is an $\in$-embedding from $V$ to $L$, this is related to my question mathoverflow.net/q/101821/1946, which is still open, but in joint work with Woodin, Magidor and others, we have a bunch of partial results.
Feb 16, 2016 at 2:21 comment added Joel David Hamkins Gödel's constructible universe is usually denoted by L, and the full set-theoretic universe is usually denoted by V. If these are different, then you can't map V to L with a functor that is the identity on finite sets, since not all finite sets will be in L. If x is not in L, then {x} is a finite set that is not in L.
Feb 16, 2016 at 2:18 comment added Theo Johnson-Freyd @JoelDavidHamkins No, because it's not a perfectly well-posed question, because I don't really know what a "model of sets" is. But here's a related question. If I'm not mistaken, among the universe U of sets, there some but not all of the sets are "constructible", which I think is called V. Is there a functor from U to V that is the identity on finite sets and takes colimits to colimits? It should be a sort of "rounding up" functor.
Feb 15, 2016 at 20:21 comment added Joel David Hamkins Is there a purely set-theoretic manner of asking the question?
Feb 15, 2016 at 18:53 answer added Simon Henry timeline score: 6
Feb 15, 2016 at 18:29 history asked Theo Johnson-Freyd CC BY-SA 3.0