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Jun 5, 2023 at 20:14 comment added ABIM @paulgarrett Right by virtue of the concavity of $t\mapsto t^p$ eh.
Oct 10, 2019 at 21:39 comment added paul garrett It might be worth noting, though, that in the space $\ell^p$ with $0<p<1$, if we don't take $p$th roots in defining the norm, then the triangle inequality still does hold.
Aug 5, 2010 at 10:04 vote accept Unknown
Apr 30, 2010 at 15:45 comment added Sergei Ivanov There are also similarly defined quasi-metrics, I've seen at least one paper that uses them as a tool.
Apr 30, 2010 at 15:36 history answered gowers CC BY-SA 2.5