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Feb 13, 2016 at 16:41 history closed Yemon Choi
YCor
Wolfgang
Andreas Thom
Myshkin
Needs details or clarity
Feb 13, 2016 at 16:14 comment added Yemon Choi Look: how are you proposing to define a functional on $\ell^\infty(\Gamma)$ if you are given a character on the full Cstar algebra and not on the reduced one? I think your previous comment answers your own question, inasmuch as I can find an actual well-defined question
Feb 13, 2016 at 2:57 answer added user75274 timeline score: 2
Feb 13, 2016 at 2:29 review Close votes
Feb 13, 2016 at 16:41
Feb 13, 2016 at 2:27 comment added truebaran For example something like this: I have an action of $\Gamma$ on $\mathbb{C}\Gamma$ which comes from the group multiplication: this defines a homomorphism from $\mathbb{C}\Gamma$ into itself. We can extend it to the whole $C^*(\Gamma)$: let us call this $\alpha$-so why not to use the same trick with $\alpha(s)f \alpha(s)^*$? But this expression doesn't make sense unless $\alpha(s)$ lives in $B(\ell^2(\Gamma))$.
Feb 13, 2016 at 2:24 comment added Yemon Choi The argument for the reduced Cstar algebra uses the fact that this is the left regular representation of the group. That is a specific assumption with specific consequences. Having a character on the full group Cstar algebra does not single out special features of the left regular representation, so I personally don't find it at all surprising that the argument for the reduced Cstar case does not extend to an argument for the full Cstar case
Feb 13, 2016 at 2:21 comment added Yemon Choi Your question, as stated above, asks: "Is it possible to deduce from the above argument ... something about the representation theory of $C^*(\Gamma)$?" The representation theory of $C^*(\Gamma)$ is the same as the unitary representation theory of $\Gamma$; what are you hoping to deduce about this representation theory?
Feb 13, 2016 at 2:18 history edited truebaran CC BY-SA 3.0
added 330 characters in body
Feb 13, 2016 at 2:11 comment added Yemon Choi The augmentation character is always a character on $C^*(\Gamma)$ for any discrete group $\Gamma$, so I do not see what one could deduce merely from knowing the existence of a character on the full $C^*$-algebra
Feb 13, 2016 at 1:31 history asked truebaran CC BY-SA 3.0