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Feb 12, 2016 at 19:20 comment added Jason Starr Actually, as updated below, there are examples where the geometric generic fiber of $f$ is everywhere nonreduced.
Feb 12, 2016 at 15:06 vote accept Omprokash Das
Feb 12, 2016 at 13:40 answer added Jason Starr timeline score: 7
Feb 12, 2016 at 10:51 comment added Jason Starr Also, because the geometric generic fiber is $S2$, this is really about the codimension $1$ part of the singular locus of the morphism. So, via Bertini, etc., you may as well assume that $X$ is a surface and $Y$ is a curve.
Feb 12, 2016 at 10:11 comment added Jason Starr If $X$ is smooth, then over a dense Zariski open subset of $Y$ the geometric fibers are LCI, hence Cohen-Macaulay. Also, if the natural map $\mathcal{O}_Y\to f_*\mathcal{O}_X$ is generically an isomorphism, then the geometric generic fiber is generically reduced. Hence the geometric generic fiber is (everywhere) reduced.
Feb 12, 2016 at 6:23 history asked Omprokash Das CC BY-SA 3.0