Timeline for Splitting subspaces and finite fields
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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Feb 12, 2016 at 13:19 | comment | added | Lev Borisov | Yes, you are right. | |
Feb 12, 2016 at 13:03 | comment | added | Peter Mueller | @Lev Borisov: This approach cannot work: Take for instance $m=2$, $n=3$ and let $T$ be the quadratic extension of $R$. Then the elements of $T$ are not in the value set you described, but $T\setminus R$ is not a subset of $S$. | |
Feb 12, 2016 at 7:22 | comment | added | Mikhail Goltvanitsa | maybe you can give an advice where I can read about values of such rational functions over finite fields? | |
Feb 11, 2016 at 6:48 | comment | added | Mikhail Goltvanitsa | Interesting idea. But I have not full proof too) | |
Feb 11, 2016 at 3:10 | history | answered | Lev Borisov | CC BY-SA 3.0 |