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Apr 28, 2022 at 19:16 comment added Dinisaur ok i just realised that the difinition of hyperbolicity used here is not the $4$-points definition for which the constant is $\operatorname{log}(2)$, but can the same reasoning still apply? are there precise relations between the constants of the different definitions or are these equivalent only under upper and lower linear bounds?
Apr 28, 2022 at 19:07 comment added Dinisaur since a geodesic triangle is always contained in a totally geodesic plane why can't we deduce immediately that the $\delta$-hyperbolicity constant of $\mathbb{H}^2$ is optimal, i.e. $\operatorname{log}(2)$?
May 5, 2010 at 13:49 vote accept Paul Siegel
Apr 30, 2010 at 4:06 comment added Sam Nead There is a Mobius transformation turning your proof into my proof. Of course, Mobius transformations have inverses... :)
Apr 30, 2010 at 3:56 history edited S. Carnahan CC BY-SA 2.5
correction; added 35 characters in body; added 55 characters in body
Apr 30, 2010 at 3:17 history answered S. Carnahan CC BY-SA 2.5