Timeline for No normal coordinates on general Finsler manifolds
Current License: CC BY-SA 3.0
11 events
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| Apr 20, 2017 at 17:01 | comment | added | ABIM | Hi Robert, I do have one critically important question on the above derivation. Do you take the Finsler function definition to require the Hessian convexity or do you only assume it is a norm on tangent spaces? If it is in the second case, do we still have (At least continuous..or maybe Bi-Lipschutz) exponential coordinates (I have come across the Bi-Lischutz case for low-regularity Riemannian manifolds. | |
| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Feb 27, 2017 at 14:03 | comment | added | Robert Bryant | @CSA: Actually, the point of my remarks is that exponential normal coordinates are well-defined in general (you don't need $F(-x)=F(x)$ for this). It's just that they are (usually) not more than $C^1$ at the origin. | |
| Feb 27, 2017 at 13:57 | comment | added | ABIM | So just to clarify if $F(-x)=F(x)$ then the exponential coordinates are well defined (as I expected)? | |
| Feb 28, 2016 at 10:42 | history | edited | Robert Bryant | CC BY-SA 3.0 |
added 764 characters in body
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| Feb 8, 2016 at 12:06 | history | edited | Robert Bryant | CC BY-SA 3.0 |
Added a clarifying statement at the end about comparing smoothness using the distance function.
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| Feb 8, 2016 at 11:43 | comment | added | ABIM | Really detailed and great answer! Thank you so much Robert! | |
| Feb 7, 2016 at 22:06 | vote | accept | ABIM | ||
| Feb 7, 2016 at 10:18 | history | edited | Robert Bryant | CC BY-SA 3.0 |
Clarified some notation and fixed some typos
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| Feb 6, 2016 at 16:13 | history | edited | Robert Bryant | CC BY-SA 3.0 |
Clarified some wording and fixed some typos
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| Feb 6, 2016 at 12:11 | history | answered | Robert Bryant | CC BY-SA 3.0 |