Timeline for Divergence of general random series and a special case
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Jul 1, 2022 at 17:53 | comment | added | Robert Israel | Chebyshev's inequality says $$\mathbb P\left(|X_n - \mu_n| \ge k_n \sigma_n\right) \le \frac{1}{k_n^2}$$ so $$\mathbb P\left(X_n > \mu_n - k_n \sigma_n\right) \ge 1 - \mathbb P\left(|X_n - \mu_n| \ge k_n \sigma_n\right) \ge 1 - \frac{1}{k_n^2}$$ | |
| Jun 30, 2022 at 12:17 | comment | added | Scriddie | How exactly are you using Chebyshev's inequality here? | |
| Feb 4, 2016 at 22:35 | history | edited | Robert Israel | CC BY-SA 3.0 |
added 71 characters in body
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| Feb 4, 2016 at 22:25 | history | answered | Robert Israel | CC BY-SA 3.0 |