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Sep 11 at 5:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Aug 12 at 4:07 history edited Jose Arnaldo Bebita CC BY-SA 4.0
edited body
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S Jul 1 at 4:38 history suggested no upstairs
Tag revision
Jun 30 at 18:52 review Suggested edits
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Jun 11, 2022 at 13:51 history edited Martin Sleziak CC BY-SA 4.0
http -> https (the question was bumped anyway)
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Jul 9, 2018 at 10:10 history edited Jose Arnaldo Bebita CC BY-SA 4.0
added GCD constraint
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Dec 8, 2016 at 20:52 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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Sep 9, 2016 at 16:27 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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Jul 11, 2016 at 14:46 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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Feb 12, 2016 at 11:59 history edited Jose Arnaldo Bebita CC BY-SA 3.0
added parentheses
Feb 7, 2016 at 21:53 history edited Jose Arnaldo Bebita CC BY-SA 3.0
inserted a brief remark about an error with elementary logic
Feb 7, 2016 at 12:19 history edited Jose Arnaldo Bebita CC BY-SA 3.0
added further details
Feb 7, 2016 at 12:11 history edited Jose Arnaldo Bebita CC BY-SA 3.0
added further details
Feb 6, 2016 at 8:38 history edited Jose Arnaldo Bebita CC BY-SA 3.0
corrected upper bound for $\sigma(q)/n$
Feb 6, 2016 at 7:10 comment added Jose Arnaldo Bebita @SylvainJULIEN, the same results have already been communicated to myself by Patrick starting December 2015. He e-mailed me a partial proof for $q^k < n$ last January 28, and did advise me that he will be posting the same to the arXiv "in the next couple of days".
Feb 6, 2016 at 6:57 history edited Jose Arnaldo Bebita CC BY-SA 3.0
corrected the incorrect upper bound for $1/n$ from ${10}^{-500}$ to ${10}^{-375}$
Feb 5, 2016 at 20:46 answer added wythagoras timeline score: 0
Feb 5, 2016 at 14:33 comment added Sylvain JULIEN Arnie, have you read this: arxiv.org/abs/1602.01591 ?
Feb 4, 2016 at 21:00 history edited Jose Arnaldo Bebita CC BY-SA 3.0
added hyperlink to Ochem and Rao's paper in Math. Comp.
Feb 4, 2016 at 20:24 history edited Jose Arnaldo Bebita CC BY-SA 3.0
removed reference to arXiv preprint of OP
Feb 4, 2016 at 20:16 history edited Jose Arnaldo Bebita
added "divisors-multiples" tag
Feb 4, 2016 at 20:14 comment added Jose Arnaldo Bebita The abundancy index of $n$, denoted by $I(n)$, is defined as the ratio $$I(n) = \frac{\sigma(n)}{n}.$$
Feb 4, 2016 at 20:13 comment added Jose Arnaldo Bebita The quasi-Euler prime of the lone spoof odd perfect number that we know of (i.e., $D = 198585576189$), is the factor $q_1 = 22021$ that has odd exponent and that makes $D$ "perfect", if we pretend that $q_1 = {{19}^2}\cdot{61}$ is "prime".
Feb 4, 2016 at 20:09 comment added Jose Arnaldo Bebita @Seva, the Euler prime of an odd perfect number is the unique prime that occurs to an odd exponent (conjectured to be $1$ by Descartes, Frenicle, and most recently by Sorli).
Feb 4, 2016 at 20:06 comment added Seva What is an "Euler prime"? What is a "quasi-Euler prime"? What is $I(n)$?
Feb 4, 2016 at 18:00 history edited Jose Arnaldo Bebita CC BY-SA 3.0
added the detail: "with Euler prime $q$" in the **Question**
Feb 4, 2016 at 17:40 history edited Jose Arnaldo Bebita CC BY-SA 3.0
fixed missing parentheses
Feb 4, 2016 at 17:32 history edited Jose Arnaldo Bebita CC BY-SA 3.0
added further details
Feb 4, 2016 at 17:13 history edited Jose Arnaldo Bebita CC BY-SA 3.0
improved the upper bound for $\sigma(q)/q = 1 + (1/q) < 1 + (1/n)$ from $6/5$ to $1 + {10}^{-500}$
Feb 4, 2016 at 14:02 history asked Jose Arnaldo Bebita CC BY-SA 3.0