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Feb 3, 2016 at 3:43 comment added nfdc23 @WillSawin: Thanks for noting my oversight when reading the original question (and for noting why it ultimately addresses the question posed as a special case).
Feb 3, 2016 at 3:40 history edited nfdc23 CC BY-SA 3.0
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Feb 3, 2016 at 3:32 comment added Will Sawin It's important to note that Sasha asked for $\operatorname{Gal}(L/K)$-cohomology and not $\operatorname{Gal}(K)$ cohomology. In particular, this is the source of the assumption that $L/K$ be Galois! To check that your answer applies, we apply a spectral sequence to equation the $\operatorname{Gal}(K)$-cohomology of a group scheme to the $\operatorname{Gal}(L/K)$ cohomology of its $\operatorname{Gal}(L)$-cohomology, then observe that its $\operatorname{Gal}(L)$-cohomology is equal to its $L$-points in degree $0$ (obvious) and vanishes in higher degree (Hilbert 90).
S Feb 3, 2016 at 2:24 history answered nfdc23 CC BY-SA 3.0
S Feb 3, 2016 at 2:24 history made wiki Post Made Community Wiki by nfdc23