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Feb 2, 2016 at 20:03 comment added Nate Eldredge Subellipticity is mostly useful as a substitute for elliptic regularity, and those definitions don't imply anything of the kind. Even if we strengthen them by adding a bracket-generating type condition, so that they do imply subellipticity in the sense of Folland, the proof of this implication is not trivial.
Feb 2, 2016 at 20:02 comment added Nate Eldredge That talk shows two (inequivalent) definitions of "subelliptic", both of which are satisfied by the Heisenberg Laplacian, which is very easy to check. If you're using one of those definitions, then I don't understand what your question is. But those are strange definitions, since they don't lead directly to any useful analytic properties; and they're satisfied by truly degenerate operators like $\partial_x^2 + \partial_y^2$ on $\mathbb{R}^3$, or the 0 operator.
Feb 2, 2016 at 18:37 comment added Z. Alfata For example, using the definition in people.emich.edu/ocalin/Contact_files/Subelliptic_Talk.pdf, we can prouve that $\Delta $ is sub-elliptic, because: $$ \Delta = X^2 +Y^2 + T^2$$ where $X,Y $ and $T$ are the vector fields on $H^3$
Feb 2, 2016 at 18:05 comment added Nate Eldredge So you mean this definition (as in Folland 1972): there exists $\epsilon > 0$ such that for each bounded open set $V$ there exists a constant $C$ such that for all $f \in C^\infty_c(V)$ we have $$\|f\|_{W^{\epsilon,2}}^2 \le C(|\langle \Delta f, f \rangle| + \|f\|_{L^2}^2)$$ If not, please state the definition you are using.
Feb 2, 2016 at 17:44 comment added Z. Alfata I would just use the definition of sub-elliptic of a operator
Feb 2, 2016 at 17:39 comment added Nate Eldredge Also, for subellipticity, do you just want the "qualitative" statement "if $\Delta u \in C^\infty$ then $u \in C^\infty$", or do you want the "quantitative" subelliptic estimates on Sobolev norms?
Feb 2, 2016 at 17:37 comment added Z. Alfata Hello, @NateEldredge, thank you for your comment. with a direct argument (for example by calculation) will be better. Thank you
Feb 2, 2016 at 17:30 comment added Nate Eldredge Non-ellipticity is easy, just check that the principal symbol is degenerate (compute determinant or whatever you like). For subellipticity, are you happy with the "big gun" of Hormander's theorem, or do you want a direct argument?
Feb 2, 2016 at 16:57 history asked Z. Alfata CC BY-SA 3.0