Timeline for Description of $\big(\ell^\infty(\mathbb N)\big)^{\!*}$ via ultrafilters
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Feb 3, 2016 at 9:17 | history | edited | smyrlis | CC BY-SA 3.0 |
added 18 characters in body; edited title
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| Feb 1, 2016 at 22:10 | history | edited | Denis Serre | CC BY-SA 3.0 |
added 5 characters in body
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| Feb 1, 2016 at 22:02 | answer | added | smyrlis | timeline score: 4 | |
| Feb 1, 2016 at 13:45 | vote | accept | smyrlis | ||
| Feb 1, 2016 at 13:29 | answer | added | Jochen Wengenroth | timeline score: 8 | |
| Feb 1, 2016 at 13:11 | history | edited | YCor |
edited tags
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| Feb 1, 2016 at 12:38 | answer | added | Eric Wofsey | timeline score: 19 | |
| Feb 1, 2016 at 12:22 | comment | added | Yemon Choi | I can't think of anything at the moment, sorry | |
| Feb 1, 2016 at 12:03 | comment | added | smyrlis | @YemonChoi: Is there any literature you could suggest? | |
| Feb 1, 2016 at 11:42 | comment | added | Yemon Choi | My guess is "no", because the norm closure of your set X may be viewed as the space of atomic finite measures on $\beta{\bf N}$, whereas $\ell^\infty({\bf N})^*$ is the space of all finite Radon measure on $\beta{\bf N}$, and it just seems very unlikely that all finite Radon measures on this space are atomic | |
| Feb 1, 2016 at 10:50 | history | asked | smyrlis | CC BY-SA 3.0 |