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Feb 12, 2016 at 11:54 comment added Lior Silberman Seconding Loren, questions about symplectic groups are best first tested on $\mathrm{Sp}_2=\mathrm{SL}_2$.
Feb 11, 2016 at 19:29 comment added LSpice @PaulBroussous has mentioned that the answer is 'no' very generally, but, as a specific example, suppose that your field has odd (or zero) characteristic, and contains a non-square $\alpha$ such that the equation $x^2 - \alpha y^2 = 1$ has a solution over the field. Then $\begin{pmatrix} x & y \\ \alpha y & x \end{pmatrix}$ lies in a torus, and it preserves the 2-dimensional symplectic form but no rational line.
Jan 31, 2016 at 3:06 vote accept kneidell
Jan 31, 2016 at 0:58 answer added Paul Broussous timeline score: 6
Jan 31, 2016 at 0:48 history asked kneidell CC BY-SA 3.0