Skip to main content
8 events
when toggle format what by license comment
Jan 31, 2016 at 13:29 vote accept Xiao-Gang Wen
Jan 30, 2016 at 5:53 comment added Qiaochu Yuan @David: don't you also need to know the converse? The converse isn't clear to me a priori.
Jan 29, 2016 at 22:02 comment added David Handelman Any ring isomorphism between representation rings that sends irreducibles to irreducibles (and vice versa) is automatically an order isomorphism. So the OP's question is equivalent to the order isomorphism question.
Jan 29, 2016 at 19:08 answer added Qiaochu Yuan timeline score: 8
Jan 29, 2016 at 19:00 comment added Xiao-Gang Wen I assume that two fusion rings $N^{ij}_k$ and $\tilde N^{ij}_k$ are the same if $N^{ij}_k$ equal to $\tilde N^{ij}_k$ after some permutations of indices.
Jan 29, 2016 at 5:32 comment added Qiaochu Yuan Unique in what sense? As a ring? As a ring with basis? As an ordered ring as in the answer below?
Jan 28, 2016 at 23:57 answer added David Handelman timeline score: 4
Jan 28, 2016 at 23:04 history asked Xiao-Gang Wen CC BY-SA 3.0