Timeline for Blocking sets in three dimensional finite affine spaces
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Jan 27, 2016 at 22:57 | comment | added | Anurag | I would like to add that a friend of mine is running a computation which has shown that $s(4) = 34 < 36$ (in case you are wondering about the sharpness of this bound $s(q) \leq 3q^2 - 3q$). He'll hopefully post more values he has computed by tomorrow. By interpolating from $s(2), s(3), s(4)$ we could make a bold (and probably wrong) conjecture that $s(q) = (5q^2 - 3q)/2$ ... But may be one can try constructing examples of size $(5q^2 - 3q)/2$ to show $s(q) \leq (5q^2 - 3q)/2$. | |
Jan 27, 2016 at 22:51 | comment | added | Anurag | Thanks. This is how I understand the second part: all lines contained in the hyperplanes $H_1, \dots, H_q$ are blocked once you have chosen a pair of intersecting lines in each of them. And every transverse which doesn't contain $P$ is blocked by $H_1 \setminus \{P\}$. Any transverse through $P$ other than the line $\ell$ intersects every $H_i$ ($i > 2$) in a point $R_i$ other than $Q_i = \ell \cap H_i$ and the line $Q_iR_i$ is parallel to one of the $q+1$ lines through $P$ in $H_1$. So, we ensure that for each line through $P$ in $H_1$, we take a parallel line through $Q_i$ in $H_i$. | |
Jan 27, 2016 at 22:08 | history | edited | Douglas Zare | CC BY-SA 3.0 |
Added upper bound.
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Jan 27, 2016 at 20:09 | history | answered | Douglas Zare | CC BY-SA 3.0 |