Skip to main content
10 events
when toggle format what by license comment
Feb 3, 2017 at 0:08 vote accept ಠ_ಠ
Jan 21, 2016 at 9:29 comment added André Henriques It's true that if you define a Lie group to be a second countable manifold equipped with a group structure, then a surjective homomorphism of Lie groups is mapped to a surjective homomorphism of Lie algebras. But this ceases to be true as soon as you allow manifolds with uncountably many connected components (think about the identity map from $\mathbb R$ with the discrete topology to $\mathbb R$ with its usual topology). So you see: it's fragile statement. And fragile statements often don't generalize very well.
Jan 21, 2016 at 3:05 comment added ಠ_ಠ @ André As far as I know, classically a surjective Lie group homomorphism is mapped to a surjective Lie algebra homomorphism by the Lie functor.
Jan 21, 2016 at 1:43 comment added André Henriques By the way, the inclusion $\mathbb Q\to \mathbb R$ is not an epimorphism in the category of rings. It is the inclusion $\mathbb Z\to \mathbb Q$ which is an epimorphism in the category of rings.
Jan 21, 2016 at 1:34 comment added Peter Samuelson Ah, right - sorry for the stupid comment.
Jan 21, 2016 at 1:24 comment added André Henriques Here, $\mathbb Q$ is endowed with the discrete topology (it is a zero-dimensional Lie group). Te map $\mathbb Q\to \mathbb R$ is an epimorphism because if $f:\mathbb R\to G$ is a homomorphism of Lie groups, then $f$ is completely determined by $f|_{\mathbb Q}$ (by continuity).
Jan 21, 2016 at 1:00 comment added Peter Samuelson What topology are you putting on $\mathbb Q$ so that it is a Lie group? And why is it an epimorphism? I know the inclusion is an epimorphism in the category of rings, but is it an epimorphism in the category of abelian groups?
Jan 21, 2016 at 0:47 comment added André Henriques I'm not sure what you mean by "the Lie functor preserves surjections in classical differential geometry". Can you try to make that statement more precise?
Jan 20, 2016 at 22:09 comment added ಠ_ಠ Ah, I hadn't realized that epis in the category of Lie groups were not precisely surjective smooth homomorphisms. I believe the Lie functor does preserve surjections in classical differential geometry, so I have edited my question.
Jan 20, 2016 at 21:18 history answered André Henriques CC BY-SA 3.0