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Jan 20, 2016 at 11:34 vote accept Sasha
Jan 20, 2016 at 11:32 vote accept Sasha
Jan 20, 2016 at 11:34
Jan 20, 2016 at 3:04 answer added R. van Dobben de Bruyn timeline score: 6
Jan 20, 2016 at 0:37 comment added pro sorry, I was confused. I take back what I wrote!
Jan 19, 2016 at 23:20 comment added pro isn't Sym k = k[x]?
Jan 19, 2016 at 22:58 comment added Sasha I mean Spec of Sym of dual. Why would that be wrong for T a point? It would say that morphisms from $X$ to $\mathbb{A}^1$ are the same as elements of the set $\Gamma(X,\mathcal{O}_X)$, which is correct, no?
Jan 19, 2016 at 19:53 comment added pro what do you mean by interpreting $\Gamma(X,O)$ as a scheme as usual? Do you mean taking Spec of it, or Spec of Sym of its dual? If the latter, then it's false (eg take X to be projective space and T = Spec k).
Jan 19, 2016 at 13:51 history asked Sasha CC BY-SA 3.0