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Timeline for Determinant of discrete Laplacian

Current License: CC BY-SA 3.0

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Jan 29, 2016 at 9:00 vote accept Matthias Ludewig
Jan 19, 2016 at 15:01 answer added Gjergji Zaimi timeline score: 3
Jan 19, 2016 at 12:43 history edited Matthias Ludewig CC BY-SA 3.0
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Jan 19, 2016 at 9:39 comment added leo monsaingeon By user35593's comment (which I didn't check but looks reasonable to me) you have lower and upper bounds on $ |det|$ in terms of what you expect, as soon as your partition is "approximately equidistant" $0<C_1\leq \frac{\Delta_i}{\Delta_j}\leq C_2$. However the scalings are different in the OP's 2 matrices: in order to stay consistent the first matrix should be multiplied by the uniform mesh $\Delta$, otherwise it doesn't make sense. Also, these matrices are the discretization of the positive operator "negative laplacian", not of the laplacian.
Jan 19, 2016 at 9:15 comment added user35593 You can prove by induction that the determinant is $\prod_{i=1}^N \Delta_i \sum_{i=1}^N \frac{1}{\Delta_i}$
Jan 19, 2016 at 8:47 history asked Matthias Ludewig CC BY-SA 3.0