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Jan 18, 2016 at 11:24 vote accept Sasha
Jan 18, 2016 at 10:36 comment added abx 1) See this Wikipedia article and the references at the end. 2) Yes, because $\mathcal{M}$ is constructed as a quotient of a fine moduli space $Q$ by an algebraic group, and one can take $S=Q$ in the above answer. 3) There is a universal bundle if and only if $r$ and $d$ are coprime -- this is a result of Ramanan, The moduli spaces of vector bundles over an algebraic curve, Math. Ann. 200 (1973), 69–84.
Jan 18, 2016 at 9:19 comment added Sasha Thanks. 1) Do you have a reference? 2) Can I replace analytic spaces by complex manifolds and it will still characterize M? 3) It seems that there will not necessarily be a universal bundle on MxX?
Jan 17, 2016 at 20:18 history answered abx CC BY-SA 3.0