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Jan 17, 2016 at 22:14 comment added Fedor Petrov @LiorSilberman exactly, and a closely related theory by Lovasz and his school.
Jan 17, 2016 at 22:03 comment added Lior Silberman This seems like the kind of problem Razborov's theory of flag algebras was designed to solve.
Jan 17, 2016 at 19:14 comment added Fedor Petrov It is up to constant factor the same problem as 'maximal number of edges without cycle of length 4', which is well known
Jan 17, 2016 at 18:56 comment added mssmath I just realized my error. How did you get a bound of $n^\frac{3}{2}$?
Jan 17, 2016 at 18:54 comment added Fedor Petrov @mssmath it is wrong already for $n=4$. Correct answer is of order $n^{3/2}$.
Jan 17, 2016 at 18:49 comment added mssmath I would like to note that if say there are at most 3 edges among a set of 4 vertices then $f(n)=n-1$ follows using Fedor's methods.
Jan 17, 2016 at 18:33 comment added mssmath I am assuming that given a set of $n$ vertices that that there are at most $n$ edges between them.
Jan 17, 2016 at 18:32 comment added Brendan McKay The Hebrew paper: renyi.hu/~p_erdos/1955-15.pdf (see your answer on the first page). The generalization would be to ask what the max density of an $n$-vertex graph can be if it has no $k$-vertex subgraph with more than $\ell$ edges. It is what Erdos calls $f$ and I guess the general solution is very difficult.
Jan 17, 2016 at 18:29 comment added Fedor Petrov @BrendanMcKay What do you call ``obvious generalization''?
Jan 17, 2016 at 18:25 comment added Brendan McKay In this 1964 paper of Erdos: renyi.hu/~p_erdos/1964-06.pdf , he attributes this result to a 1955 Hebrew paper of himself (ref [6]).
Jan 17, 2016 at 18:23 vote accept mssmath
Jan 17, 2016 at 18:15 comment added Brendan McKay Interestingly these have density only $\frac12+o(1)$ as $n\to\infty$. Do you know if the limiting density is known for the obvious generalization?
Jan 17, 2016 at 18:02 history answered Fedor Petrov CC BY-SA 3.0