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Jan 17, 2016 at 20:46 comment added Christian Remling I still don't think this works. For starters, the fundamental solution is a function of $(x,y)\in\mathbb Z^2$, not $\in\mathbb R^2$. (By the way, I didn't downvote.)
Jan 17, 2016 at 19:41 comment added Bazin @Christian Remling I did edit my answer.
Jan 17, 2016 at 19:40 history edited Bazin CC BY-SA 3.0
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Jan 16, 2016 at 19:19 comment added Christian Remling No, it isn't. This is undefined for various reasons ($(k,l)=(x,y)$, plus the sum is badly divergent), and even if it weren't, then it would be constant.
Jan 16, 2016 at 16:41 review Low quality posts
Jan 16, 2016 at 18:31
Jan 16, 2016 at 16:23 history answered Bazin CC BY-SA 3.0