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Jan 15, 2016 at 15:13 comment added Suvrit @FedorPetrov thanks (for your rhetoric question!) all of what I said goes thru trivially to $R^n$...incl. Schoenberg's theorem
Jan 15, 2016 at 14:54 comment added Fedor Petrov Does not Schoenberg's theorem work in $\mathbb{R}^n$?
Jan 15, 2016 at 14:54 comment added Dirk I guess $|x|$ is the euclidean norm in n dimensions...
Jan 15, 2016 at 14:47 comment added Suvrit @Dirk: I answered the question written in the title...I did not look at the main text :-)
Jan 15, 2016 at 14:44 comment added Dirk Not sure if you answered the right question. Note that dimension of the domain is also $n$.
Jan 15, 2016 at 14:36 history edited Suvrit CC BY-SA 3.0
added explicit proof for $a>2$ case
Jan 15, 2016 at 13:04 history answered Suvrit CC BY-SA 3.0