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Feb 11, 2022 at 15:00 answer added Andrea Ferretti timeline score: 4
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Mar 15, 2016 at 6:59 comment added Bruno Stonek In this article by Kapranov arxiv.org/pdf/1512.07042v1.pdf , notably in page 23, there a table showing the "significance" of the first four stable stems.
May 10, 2015 at 16:19 answer added Mark Grant timeline score: 10
Apr 29, 2010 at 1:00 answer added Daniel Moskovich timeline score: 13
Apr 28, 2010 at 23:34 answer added Igor Belegradek timeline score: 14
Apr 28, 2010 at 20:45 comment added Andrew Stacey tea.mathoverflow.net/discussion/371/…
Apr 28, 2010 at 20:37 answer added Tim Perutz timeline score: 29
Apr 28, 2010 at 17:34 answer added rat timeline score: 4
Apr 28, 2010 at 16:15 comment added Andrea Ferretti Well, I'd say more than related.
Apr 28, 2010 at 16:05 answer added José Figueroa-O'Farrill timeline score: 26
Apr 28, 2010 at 14:35 comment added j.c. This question seems related: mathoverflow.net/questions/16495/…
Apr 28, 2010 at 13:49 answer added Paul Siegel timeline score: 49
Apr 28, 2010 at 13:13 answer added Tyler Lawson timeline score: 23
Apr 28, 2010 at 12:24 answer added Pete L. Clark timeline score: 12
Apr 28, 2010 at 12:10 comment added Steve Huntsman Here is a (silly) application of FLT due to Schultz that is on Dick Lipton's blog. Proposition. If $n \ge 3$, then $\sqrt[n]{2}$ is irrational. Proof: suppose $\sqrt[n]{2} = z/y$ for $z$ and $y$ positive integers. Taking $n$th powers yields that $2 = z^n/y^n$, so $y^n + y^n = z^n$. By FLT, there is a contradiction. $\Box$ See rjlipton.wordpress.com/2010/03/31/april-fool
Apr 28, 2010 at 12:07 comment added Andrew Stacey @Pete: I agree with your second sentence completely. However, if you had turned it round, I would have been unhappy. My contention (and I feel as though it's getting more exposure than it's worth!) is that for something to convey lots of information, it must be complicated in some way. (I don't like the word "deep", but that's just a personal dislike.) As for your emphasised sentence, again I'm in complete agreement. But nonetheless, I'd like to know if they have had significant applications! If nothing else, I could sell my subject a bit better than I do at the moment!
Apr 28, 2010 at 12:02 comment added Harry Gindi Well, they could potentially allow us to compute homotopy group(oid)s like homology groups if we use the higher Van Kampen theorem(s) à la Ronnie Brown, but this sort of computation is still going to be extremely laborious (and probably highly impractical) given that n-groupoids/crossed complexes don't really avail themselves to explicit computation. Of course we'd have to actually compute the homotopy groupoids rather than the homotopy groups of the spheres, but it doesn't seem like such a stretch to be able to compute the whole n-groupoid from having all of the homotopy groups.
Apr 28, 2010 at 11:54 comment added Pete L. Clark As I wrote in a previous comment, I find your link between complication and usefulness to be quite strange. Just because something is complicated doesn't mean that it conveys more information. Maybe you mean "deep" instead. Certainly there's lots of evidence that the homotopy groups of spheres have a potentially infinite richness of algebraic and topological information: therefore, they are indubitably worthy of study. But have they had significant applications? So far as I know they haven't, and there's nothing wrong with that. Fermat's last theorem has no applications whatsoever...
Apr 28, 2010 at 11:27 history asked Andrew Stacey CC BY-SA 2.5