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Apr 30, 2010 at 19:58 comment added Brad Rodgers Alright. I think I fixed everything. I did finally take a look at Hardy; I'm not sure if his proof is properly 'homotopic' to this one, but the main idea is still to take Mellin transforms.
Apr 30, 2010 at 19:55 history edited Brad Rodgers CC BY-SA 2.5
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Apr 29, 2010 at 19:29 comment added Brad Rodgers Actually, I had another think over this today, and I'm making a mistake in using dominated convergence. If nothing else, one (I think) can get by establishing the interchange of summation and integration for large enough $s$, and then invoke analytic continuation, but the result ought to have a real variable proof. Perhaps until I've thought about it more thoroughly, Gerald's reference to Hardy is the place to go...
Apr 29, 2010 at 10:45 vote accept David E Speyer
Apr 28, 2010 at 19:14 history edited Brad Rodgers CC BY-SA 2.5
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Apr 28, 2010 at 19:11 comment added Brad Rodgers You're right; it's a nontrivial point. I added an argument to the post justifying it.
Apr 28, 2010 at 19:06 history edited Brad Rodgers CC BY-SA 2.5
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Apr 28, 2010 at 12:23 comment added David E Speyer Possibly dumb question: are you sure we can interchange summation and integration? The obvious fact is that $\sum a_n/n^s = (1/\Gamma(s)) \sum \int \cdots$, while your argument needs $\int \sum$.
Apr 28, 2010 at 10:11 history edited Brad Rodgers CC BY-SA 2.5
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Apr 28, 2010 at 8:41 history answered Brad Rodgers CC BY-SA 2.5