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Jan 12, 2016 at 16:52 vote accept batconjurer
Jan 12, 2016 at 14:40 history edited batconjurer CC BY-SA 3.0
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Jan 12, 2016 at 13:39 answer added Chris Godsil timeline score: 8
Jan 12, 2016 at 13:35 comment added batconjurer Sure, I can give that a shot.
Jan 12, 2016 at 13:13 comment added Ilya Bogdanov As for me, possible counterexanples probably can be found among pairs of isospectral trees. Do you have any software to check whether your condition is satisfied? If so, I would suggest to test some pairs from, e.g., pubs.acs.org/doi/pdf/10.1021/ci970242r (parhaps, those on Fig. 5?).
Jan 12, 2016 at 12:53 comment added batconjurer Just a sequence of edges $(v_1,v_2),(v_2,v_3),\dots,(v_{k-2},v_{k-1})$. And I'm also requiring that $v_1$ be the root. The paths are allowed to end wherever, and any amount of backtracking is allowed; these walks do not have to be simple. They can repeat edges and vertices. It's quite possible I missed some easy counterexample.
Jan 12, 2016 at 12:51 review Close votes
Jan 12, 2016 at 13:42
Jan 12, 2016 at 12:35 comment added Vladimir Dotsenko Can you be a bit more specific about what you mean by a walk of length $k$? some obvious interpretations admit obvious counterexamples, so some clarity would help.
Jan 12, 2016 at 11:59 history asked batconjurer CC BY-SA 3.0