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Sep 24, 2019 at 12:13 comment added Thomas Dybdahl Ahle Right, so $\exp(-x^2/2) = \frac{1}{n\log n}$, which is what @Anthony describes as "on the cusp of summability" since $\frac{1}{n\log n\,(\log\log n)^2}$, say, is summable.
Jan 12, 2016 at 12:11 comment added Sebastian Goette How does this explain the $\sqrt{log\log n}$?
Jan 12, 2016 at 11:15 review Late answers
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Jan 12, 2016 at 12:11
Jan 12, 2016 at 10:58 history answered Lan GAO CC BY-SA 3.0