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Jan 11, 2016 at 18:56 vote accept Dominic van der Zypen
Jan 11, 2016 at 16:43 vote accept Dominic van der Zypen
Jan 11, 2016 at 16:43
Jan 11, 2016 at 16:20 comment added Dominic van der Zypen Sorry forgot criterion 1
Jan 11, 2016 at 16:18 history edited Dominic van der Zypen CC BY-SA 3.0
Forgot criterion 1
Jan 11, 2016 at 16:15 vote accept Dominic van der Zypen
Jan 11, 2016 at 16:19
Jan 11, 2016 at 14:26 answer added David Bevan timeline score: 3
Jan 11, 2016 at 14:25 comment added bof Of course $fa)\ne f(b)$ if $a\cap b=\emptyset$ so you could have just said $f$ is injective. Your selector can't exist if $|\mathcal F|\gt|X|$ so $\mathcal F=\binom X1+\binom X2$ is a counterexample if $|X|\ge2.$
Jan 11, 2016 at 9:32 answer added Michael Renardy timeline score: 5
Jan 11, 2016 at 9:17 history asked Dominic van der Zypen CC BY-SA 3.0