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Apr 29, 2010 at 4:39 vote accept Tuan
Apr 28, 2010 at 16:39 comment added JSE Just a note -- if you think of X as Pic^1(X) and J as Pic^0(X), this is (over the generic fiber) just the composition of the isomorphism Pic^n(X) = Pic^(X) coming from your choice of D, with multiplication-by-n from Pic^1(X) to Pic^n(X).
Apr 28, 2010 at 5:48 history answered naf CC BY-SA 2.5