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Jan 8, 2016 at 18:18 comment added Carlo Beenakker @BenCrowell --- in the case of a classical wave, for momentum read wavenumber (discretized at $k_n$), and for mass read cutoff frequency $\omega_n=ck_n$, so that the dispersion relation in three-dimensional space is $\omega^2=(ck)^2 +\omega_n^2$.
Jan 8, 2016 at 16:24 comment added user21349 The question is about classical physics. When you refer to momentum, is that really interchangeable with wavenumber (inverse wavelength)?
Jan 8, 2016 at 12:45 history edited Carlo Beenakker CC BY-SA 3.0
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Jan 8, 2016 at 12:39 history answered Carlo Beenakker CC BY-SA 3.0