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Jan 7, 2016 at 18:12 comment added Steven Landsburg If the projective dimension of $B$ is at most $2$, then $A$ is projective. If the projective dimension of $B$ is $3$, then the projective dimension of $A$ is at most $1$. If the projective dimension of $B$ is greater than $3$, then the projective dimension of $A$ is exactly two less than the projective dimension of $B$.
Jan 7, 2016 at 18:07 answer added Vladimir Dotsenko timeline score: 1
Jan 7, 2016 at 17:49 comment added Chan In the first instance any field, finite field, or PID. Information on more general rings would be useful also though.
Jan 7, 2016 at 17:48 comment added Qiaochu Yuan It follows that $[A] = [B]$ in the quotient of the Grothendieck group $K_0(R)$ by the subgroup generated by $[R]$.
Jan 7, 2016 at 17:46 comment added Vladimir Dotsenko So how general would be the class of rings you care about?
Jan 7, 2016 at 17:43 comment added Chan Note I have removed the condition $r \geq q$ (it was a mistake!).
Jan 7, 2016 at 17:41 history edited Chan CC BY-SA 3.0
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Jan 7, 2016 at 17:26 comment added Chan For example, I want to know what can be said about relative homology groups $H_1(X,A)$ and $H_0(X,A)$ when it is known that $H_1(A) = 0$, $H_1(X) \cong R^p$, and the connectivity of $A$ and $X$ is $r$ and $q$, respectively. This is just an analogy, but should suffice. Computed means compute $H_1(X,A)$ and $H_0(X,A)$ in the usual sense (or at least determine rank).
Jan 7, 2016 at 17:15 comment added Vladimir Dotsenko Can you be a bit more specific about why you need this? When $R$ is a vector space, for instance, all the answers are essentially trivial. When $R$ is a PID (e.g. $\mathbb{Z}$), it is also quite easy to give very precise answer. But it all depends on the generality you care for. Also, it would help if you explain what "computed" means in question 1).
Jan 7, 2016 at 16:57 review First posts
Jan 7, 2016 at 17:30
Jan 7, 2016 at 16:53 history asked Chan CC BY-SA 3.0