Timeline for Is there a formula for the Frobenius-Schur indicator of a rep of a Lie group?

10 events

when toggle format	what		by	license	comment
Dec 27, 2022 at 17:51	comment	added	LSpice		@ClaudioGorodski's answer, referenced above.
Jan 30, 2016 at 14:17	comment	added	Mikhail Borovoi		@JimHumphreys: Corrected!
Jan 30, 2016 at 14:16	history	edited	Mikhail Borovoi	CC BY-SA 3.0	edited body
Jan 30, 2016 at 14:07	comment	added	Jim Humphreys		A small point of confusion is the switch to the index $n$ in your summation $(*)$.
Jan 9, 2016 at 7:40	comment	added	Mikhail Borovoi		Idea of proof: One constructs a Lie subalgebra $\mathfrak{g}_1\subset \mathrm{Lie}\,G$ isomorphic to $\mathfrak{sl}_2$ and a $\mathfrak{g}_1$-invariant irreducible subspace $V_1\subset V$ with highest weight $\sigma(\lambda)$. The restriction of the bilinear form to $V_1$ is non-degenerate. .A $\mathfrak{g}_1$--invariant bilinear form on $V_1$ is symmetric if and only if $\sigma(\lambda)$ is even.
Jan 8, 2016 at 23:08	vote	accept	André Henriques
Jan 11, 2016 at 0:02
Jan 8, 2016 at 20:06	history	edited	Mikhail Borovoi	CC BY-SA 3.0	added 632 characters in body
Jan 7, 2016 at 22:32	history	edited	André Henriques	CC BY-SA 3.0	added 98 characters in body
Jan 7, 2016 at 22:08	history	edited	Mikhail Borovoi	CC BY-SA 3.0	added 1391 characters in body
Jan 7, 2016 at 15:32	history	answered	Mikhail Borovoi	CC BY-SA 3.0