Timeline for Does Alexandrov space satisfy a reverse doubling condition?
Current License: CC BY-SA 3.0
20 events
| when toggle format | what | by | license | comment | |
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| Apr 12, 2017 at 16:26 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 13, 2017 at 15:51 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Feb 11, 2017 at 15:14 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 12, 2017 at 15:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 13, 2016 at 14:17 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Nov 13, 2016 at 13:40 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Oct 14, 2016 at 13:15 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 14, 2016 at 13:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 15, 2016 at 11:24 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jul 16, 2016 at 10:33 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jun 16, 2016 at 10:16 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 17, 2016 at 9:45 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 17, 2016 at 21:42 | answer | added | John Harvey | timeline score: 1 | |
| Jan 6, 2016 at 15:19 | comment | added | Shman | @SebastianGoette Thanks for you suggestion. | |
| Jan 6, 2016 at 15:18 | history | edited | Shman | CC BY-SA 3.0 |
added 19 characters in body; edited title
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| S Jan 6, 2016 at 10:22 | history | suggested | Sebastian Goette | CC BY-SA 3.0 |
Three typos corrected
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| Jan 6, 2016 at 10:13 | comment | added | Sebastian Goette | I think you have to bound $r$ from above. Otherwise consider $S^n$ with the standard metric and put $r=\pi$. Then the two balls are the same (except for the antipode). Even worse: flat $\mathbb R^n$ has quotients of arbitrarily small diameter. But maybe you stand a chance if you demand that $r\le\frac12\mathrm{diam}(X)$. | |
| Jan 6, 2016 at 10:08 | review | Suggested edits | |||
| S Jan 6, 2016 at 10:22 | |||||
| Jan 6, 2016 at 10:01 | review | First posts | |||
| Jan 6, 2016 at 10:09 | |||||
| Jan 6, 2016 at 9:59 | history | asked | Shman | CC BY-SA 3.0 |